The galileo space probe was launched on its long journey past several planets in 1989, with an ultimate goal of jupiter. its power source is 15.6 kg of 238 pu, a by-product of nuclear weapons plutonium production. electrical energy is generated thermoelectrically from the heat produced when the 5.59-mev a particles emitted in each decay crash to a halt inside the plutonium and its shielding. the half-life of 238 pu is 87.7 years. (the atomic mass of 238 pu is 238.05 u.) (a) what was the original activity of the 238 pu in becquerel? bg (b) what power was emitted in kilowatts? kw (c) what power (in kw) was emitted 13.0 y after launch? you may neglect any extra energy from daughter nuclides and any losses from escaping y rays. kw

As newton's first law states a object in motion stays in motion

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    m₁v₁ + m₂v₂ = (m₁ + m₂)vmomentum is conserved.the left-hand side of the equation represents the momentum in the system before the collision.the right-hand side represents the momentum in the system after the collisionm₁ and v₁ represents the mass and the velocity of the physics blockm₂ and v₂ represents the mass and velocity of the ball of puttyv represents the final velocity of the combined mass.the question states the two masses stick together. they combined mass has its own velocity with the body mass the sum of the two objects' massestheir combined momentum is (m₁ + m₂)vto find the magitude of (m₁ + m₂)v, we need to add the vectors on the left-hand side of the equation: m₁v₁ + m₂v₂.note the diagram. i have positioned the vectors in accordance with their directions.the magnitude of the resultant can be calculated using the pythagorean theorem since this is a right triangle situation (north and west are perpendicular)|(m₁ + m₂)v| =  √[ (m₁v₁)² + (m₂v₂)² ]|(m₁ + m₂)v| =  √[ (1.5kg·8.0m/s)² + (0.40kg·20m/s)² ]|(m₁ + m₂)v| =  14.4 kg m/sfor two significant figures (assuming that 20m/s is two), this rounds to 14 kg m/s

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