In deep space( far from other objects) a 3000 of asteroid travels at 500 m/s in the xy plane in the east north east direction. if that’s = 30 degrees and the asteroid passed through the x axis at x= 200 m, what is the angular momentum measured around the origin (1.5x10^8)k
(3x10^8)k
-(3x10^8)k
0 kg m^2/s
-(1.5x10^8)k

angular momentum = 1.5 × k

option 1st is correct

Explanation:

Given data

mass = 3000

velocity = 500 m/s

angle = 30 degree

x = 200 m

to find out

angular momentum

solution

we know angular momentum  about origin that is

angular momentum = x × p

angular momentum = x × m × v ×sinθ

put here all these value

angular momentum = 200 × 3000 × 500 ×sin30

angular momentum = 300000000 × 0.5

angular momentum = 150000000 k

angular momentum = 1.5 × k

so option 1st is correct

less than one you can't create energy

answer: at 24 february, 2014 the population gets twice of its initial population.

explanation:

since we have given that

the population for alpha city, t years after january 1, 2004 is given as

first we find out the initial population, i.e. t=0,

so, our quadratic equation becomes,

according to question, we have said that if the population has twice its initial population, then it becomes

so, time taken to reach this above mentioned population is given by

now, we know that time can't be negative so, we take t=9.149 years.

hence, at 24 february, 2014 the population gets twice of its initial population.