A20-μf capacitor has a charge of 60 μc. how much energy is stored in this capacitor? a) 100 μj b) 80 μj c) 90 μj d) 70 μj e) 110 μj

C...90

Explanation:

Energy stored = 1/2 of(Charge × Voltage)

then substitute Voltage with (Charge ÷ Capacitance)

Then obtain the formula for energy stored as

E = 1/2 of (Charge)^2 ÷ Capacitance

= 0.5 x (60^2÷20)

;Energy stored = 90

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d₁ = displacement of tern from arctic to antarctic = 11000 miles

d₂ = displacement of tern from antarctic to arctic =   - 11000 miles

d = total displacement for the journey

total displacement for the journey is given as

d = d₁ + d₂

d = 11000 + (-11000)

d = 0 miles

t₁ = time of travel from arctic to antarctic = 3 months = 3 x 30 days = 90 days

t₂ = time of travel from antarctic to arctic = 3 months = 3 x 30 days = 90 days

t = total time of travel

total time of travel is given as

t = t₁ + t₂

t = 90 + 90

t = 180 days

average velocity is given as

average velocity = total displacement/ total time

v = d/t

v = 0/180

v = 0 miles/day