An object has a half-life of 3400 years. the initial amount is 24g. how long until 1 gram remain?

1.56 x 10^4 years

Explanation:

Half life, T = 3400 years

initial amount, No = 24 g

Amount remaining, N = 1 g

Let λ be the decay constant.

λ = 0.6931 / T = 0.6931 / 3400 = 2.039 x 10^-4 per year

Let the 1 g amount is remaining in time t.

Take log on natural base on both the sides

t = 1.56 x 10^4 years

no sign of dia of fuel cell

1.195000

explanation:

total mass=0.0117+0.0137+0.0881+0.0111

total mass= 0.01172kg

total velocity = 0.283-0.743+0.871-0.799+0.155+0.637+0.301=0.102

momentum=mv=0.1172*0.102=1.195000//