A1300-turn coil of wire that is 2.10 cm in diameter is in a magnetic field that drops from 0.130 t to 0 t in 12.0 ms. the axis of the coil is parallel to the field.
question: what is the emf of the coil? (in v)

4.875 V

Explanation:

N = 1300

diameter = 2.10 cm

radius = half of diameter = 1.05 cm

B1 = 0.130 T

B2 = 0 T

t = 12 ms

According to the law of electromagnetic induction,

Where, Ф be the magnetic flux linked with the coil

e = 4.875 V

newton's first law of motion

i really dont know but i will try okay.

so i think u would just add all them up and get your answer..