Physics, 27.08.2019 16:20 blacee01

Consider an electron being ejected from the surface of a heated filament at nearly zero specd [a] through what potential difference must it be accelerated to achieve a speed of 8.4x106m/s? any relativistic effects can be neglected [b] what is the minimum b-field required to cause the electron in part [a] above to move in a circular orbit of radius r 5.0 cm?

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Answer from: omojay1257

The potential difference and the magnetic field are 200.655 V and $9.55\times10^{-4}\ T$

Explanation:

Given that,

Speed $v=8.4\times10^{6}\ m/s$

radius = 5.0 cm

We need to calculate the potential difference

We know that,

The kinetic energy acquired by electron

$\dfrac{1}{2}mv^2=q\Delta V$

$\Delta V=\dfrac{1}{2}\times\dfrac{mv^2}{q}$

Where, m = mass of electron

q = charge

v = velocity

Put the value into the formula

$\Delta V=\dfrac{9.1\times10^{-31}\times(8.4\times10^{6})^2}{2\times1.6\times10^{-19}}$

$\Delta V=200.655\ V$

(b). We need to calculate the magnetic field

Using formula of magnetic field

$B=\dfrac{mv}{qr}$

Put the value into the formula

$B=\dfrac{9.1\times10^{-31}\times8.4\times10^{6}}{1.6\times10^{-19}\times5.0\times10^{-2}}$

$B=9.55\times10^{-4}\ T$

Hence, The potential difference and the magnetic field are 200.655 V and $9.55\times10^{-4}\ T$

Answer from: jlong2043

a) 200 v

b )9.555 x 10⁻⁴ T

Explanation:

Equation for electron acceleration under potential difference

q V = 1/2 mv²

V is potential diff , v is velocity after acceleration, q is charge on electron.

V= .5 x 9.1x 10⁻³¹ x( 8.4 x 10⁶)² / 1.6 x 10⁻₁¹⁹

= 200.655 V

b ) radius of circular orbit in a magnetic field of electron

r = $\frac{mv}{qB}$

B ) magnetic field required =

$\frac{mv}{qr}$

= 9.1 x 10⁻³¹ x 8.4 x 10⁶ / 1.6 x 10⁻¹⁹ x 5 x 10⁻²

9.55 x 10⁻⁴ T

Answer from: Quest

we need answer choices

Answer from: Quest

a solenoid is created by wrapping a l = 90 m long wire around a hollow tube of diameter d = 4.5 cm. the wire diameter is d = 0.9 mm. the solenoid wire is then connected to a power supply so that a current of i = 9 a flows through the wire.

randomized variablesl = 90 m

d = 4.5 cm

d = 0.9 mm

i = 9 a

write an expression for the number of turns, n, in the solenoid. you do not need to take into account the diameter of the wire in this calculation.

calculate the number of turns, n, in the solenoid.

write an expression for the length of the solenoid (l2) in terms of the diameter of the hollow tube d.

calculate the length of the solenoid (l2) in meters.

calculate the magnitude of the magnetic field at the center of the solenoid in teslas.

explanation:

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