Asimple circuit has a 12.0v12.0v battery and three resistors of 6.0ω6.0ω connected in parallel. if the current through the battery is 4.0a4.0a , what is the internal resistance of the battery?

The internal resistance of the battery is 1.0 Ω.

Explanation:

Given that,

Voltage = 12,0 V

Resistance of each resistor = 6.0 Ω

Current = 4.0 A

When three resistors are connected in parallel.

We need to calculate the resistance

Using formula of parallel

Here, R₁ = R₂ = R₃

The equivalent resistance is

We need to calculate the internal resistance

Using ohm's law

Where, R = resistance

r = internal resistance

V = voltage

I = current

Put the value into the formula

Hence, The internal resistance of the battery is 1.0 Ω.

the working equation for the angular size is the product of the physical size and 360 degrees divided by the product of two pi and distance from earth. the minimum size would be 0.559 degrees while the maximum size would be 0.49 degrees.