Let the radius of the circular segment be 105 m, the mass of the car 2011 kg, and the coefficient of the static friction between the road and the tire 0.7. find the magnitude of the normal force n which the road exerts on the car at the optimal speed (the speed at which the frictional force is zero) of 85 km/h. the acceleration due to gravity is 9.8 m/s 2 . answer in units of n.

Explanation:

Let N be the reaction force making angle α with the vertical.

So N Cos α = mg ( this makes friction zero )

N Sin α = mv²/r ( centripetal force is provided by sin component of N)

Squiring and adding

N = m( g² + v⁴/r² )^1/2

Putting the values

N = 2011 X ( 9.8² + 23.61⁴/105² )^1/2 [ v = 23.61 m/s given , radius r = 105 m ]

N = 22382 N

answer would be letter choice (a),   a ball resting on a shelf. would be another example of potential energy   >   stored energy > not moving.

a ball spinning on a finger   >   kinetic energy > moving energy

a ball rolling on the ground   >   kinetic energy   > moving energy

a   ball flying through the air   > kinetic energy   >   moving energy

hope that                                         : )

a.) travels faster in solids because the particles are closer together.

air is a gas water is a liquid