You have a lens whose focal length is –6.25 cm. you place an object on the axis of the lens at a distance of 10.7 cm from it. how far is the object\'s image from the lens (as a positive quantity)?

3.95 cm

Explanation:

focal length of the lens, f = - 6.25 cm

distance of object from the lens, u = - 10.7 cm

Let the distance of image from the lens is v.

Use lens equation

v = - 3.95 cm

Thus, the distance of image from the lens is 3.95 cm as the same side of object.

see the picture for the vector

the magnitude of the vector by pythagorean theorem

r = √( (-10)^2 + (3)^2 ) = √109

magnitude = √109 units

the direction angle between vector and x-axis is

tan^(-1)(3/10) = 16.699

so the direction is approximately 16.7 degrees north of west

answer is slate

hope this