In a double-slit experiment, the third-order maximum for light of wavelength 520 nm is located 17 mm from the central bright spot on a screen 1.6 m from the slits. light of wavelength 630 nm is then projected through the same slits. how far from the central bright spot will the second-order maximum of this light be located?

The distance from the central bright spot is 13.73 mm.

Explanation:

Given that,

Wavelength = 520 nm

Width d= 17 mm

Distance L= 1.6 m

Order = 3

We need to calculate the distance from the central bright spot

Using formula of distance

Put the value into the formula

Now, the wavelength is changed to 630 nm

We  need to calculate the distance from the central bright spot with the second order of this light

Hence, The distance from the central bright spot is 13.73 mm.

air exerts forces on falling objects near earth’s surface.

explanation:

the term 'free falls' refer to object that are falling towards the earth, in a situation in which gravity is the only force acting on the object.

for an object in free fall, the acceleration is constant (g, the gravitational acceleration), and so the velocity of the object constantly increases.

for objects near earth's surface, there is always another force acting on the object: the resistance due to the air. this force is opposed to the direction of fall of the object, and it is proportional to the velocity of the object, so as the object falls down, this force increases up to a point when it balances the force of gravity, and the object continues its motion at constant velocity (called terminal velocity). since in this case gravity is not the only force acting on the object, we are not in a situation of free fall.