To travel at a constant speed of 16.6 meters per second on a level road for 2.81 hours, a car must exert a constant force of 343 newtons to overcome air resistance. how much charge in coulombs must the 10.9 battery move in order to maintain this force? remember that power = energy / time and power = force x velocity. one hour = 3600 seconds.

Q = 5.28 x 10⁶.

Explanation:

Power consumption of car = Force ( F ) x velocity ( v )

= 343 x 16.6 watt.

time = 2.81 hours

= 2.81 x 3600 s

Energy consumption = power x time

= 343 x 16.6 x 2.81 x 3600

=57.6 x 10⁶ J

energy output of battery = voltage x charge

= 10.9 x Q

Energy consumption by car = energy output of battery

10.9 x Q = 57.6 x 10⁶

Q = 5.28 x 10⁶.

the amount of current in the coil

we're given that v₀ = 0 and a = 5.4 m/s². therefore, since v = at + v₀ for constant acceleration the equation for velocity is

after 28s,

m/s

which i would round to 150 m/s as my final answer