A481-m long spaceship passes by an observer at the speed of 2.70×10^8 m/s. what length does the observer measure for the spaceship?

209.66 m

Explanation:

Given:

Original length of the spaceship, L = 481 m

Speed of the spaceship, v = 2.70 × 10⁸ m/s

Now,

using the concept of length contraction, we have

where,

L' is the observed length

c is the speed of the light

Thus,

on substituting the respective values, we get

or

L'  = 209.66 m

gravititional force is a force that is acting around you, it is non-contactable and it is a force that pulls you to the core of the earth.

brainliest

answer: 802.3 kilo joules of energy represents 191.75 kilo calorie of energy.

explanation:

energy released during combustion of one mole methane = 802.3 kilo joules

if 1 kilo joule = 0.239006   kilo calorie

then ,802.3 kilo joule will be = 802.30.239006 kilo calorie

802.3 kilo joule = 191.75 kilo calorie

hence, the energy in kilo calorie is 191.75 kilo calorie.