Aring of brass has an inner diameter of 5.000 cm when it is at room temperature (20°c). it needs to slip over a pipe with a diameter of 5.005 cm. if the brass ring is heated, it will be able to fit over the pipe. what temperature should the ring be heated to?

temperature t2 is  72.63°C

Explanation:

given data

diameter d1 = 5.000 cm

temperature t1 = 20°C

diameter d2 = 5.005 cm

to find out

temperature t2

solution

we will apply here equation of coefficient of linear for brass that is

α = d2 -d1 / d1(t2 -t1)     .........................1

put here all value and find t2

19 × = ( 5.005 - 5 ) / 5( t2 - 20 )

solve it and we get t2

t2 = 20  + 52.63

t2 = 72.63

so temperature t2 is  72.63°C

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