Two speakers are placed 4.5m apart, playing a coherent 660 hz tone. a listener is at a point 0.20 m from one speaker, on the line between the two speakers. the listener increases the frequency until the loudness they hear reaches a maximum. calculate the first frequency at which this occurs. take the speed of sound in air to be 344 ms-1.

The first frequency is 671 Hz.

Explanation:

Given that,

Frequency = 660 Hz

Distance from one speaker = 0.20 m

Distance between two speakers = 4.5 m

Speed of sound = 344 m/s

We need to calculate the path difference

Path difference = 4.3-0.20 =4.1 m

We need to calculate the frequency

Using formula of path difference

Here, n = 8

Because, the frequency is less then 660 Hz at n = 7.

Hence, The first frequency is 671Hz.

double the distance = divide strength by 4