Acharge of 7.00 mc is placed at opposite corners corner of a square 0.100 m on a side and a charge of -7.00 mc is placed at other opposite corners. determine the magnitude and direction of the force on right lower corner. explain.

4.03\times10^{7}N[/tex], 135°

Explanation:

charge, q = 7 mC = 0.007 C

charge, - q = - 7 mC = - 0.007 C

d = 0.1 m

Let the force on charge placed at C due to charge placed at D is FD.

The direction of FD is along C to D.

Let the force on charge placed at C due to charge placed at B is FB.

The direction of FB is along C to B.

Let the force on charge placed at C due to charge placed at A is FA.

The direction of FA is along A to C.

The net force along +X axis

The net force along +Y axis

The resultant force is given by

The angle from x axis is Ф

tan Ф = - 1

Ф = -45°

Angle from + X axis is 180° - 45° = 135°

1= 26.17

2= 1.17

3=30.86

4=5.86

just took the assigment on edge