Acapacitor that is initially uncharged is connected in series with a resistor and a 407.1 vemf source with negligible internal resistance. just after the circuit is completed, the current through the resistor is 0.850 maand the time constant for the circuit is 6.20 s. part a: what is the resistance of the resistor?
part b: what is the capacitance of the capacitor

Resistance,

Given:

V = 407.1 V

Current through the resistor, I = 0.850 mA =

Time constant for the circuit,

Solution:

Initially the capacitor is uncharged, the current in the circuit remains same.

Thus

At t = 0

the current in the circuit, I =

Therefore,

Resistance, R =

R =

Now, for calculation of Capacitance, C:

Time constant for the circuit,

coil wire, increase current, put iron inside the coil

2b2t

explanation:

2b2t