Physics, 02.09.2019 20:20 Hudman57

Calculate the mutual force of repulsion between two charged spheres 2 cm apart of the repulsive force for a 1 cm separation is 16 n.

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Answer from: akdubgirlp7pe1v

Force of repulsion is 4 N.

Explanation:

It is given that,

If separation between the charged sphere, r = 1 cm = 0.01 m

Force of repulsion, F = 16 N

We need to find the force of repulsion (F') when the separation between the spheres is r' = 2 cm = 0.02 m

The force of attraction or repulsion is given by :

$F=k\dfrac{q_1q_2}{r^2}$

i.e. $F\propto \dfrac{1}{r^2}$

So, $\dfrac{F}{F'}=\dfrac{r'^2}{r^2}$

$\dfrac{16}{F'}=\dfrac{0.02^2}{0.01^2}$

F' = 4 N

So, the force of repulsion between the spheres is 4 N when the separation is 2 cm. Hence, this is the required solution.

Answer from: Quest

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