Advanced photodiode detectors have a second light-emitting diode, operating at a wavelength of 2.0 × 10-7 m, to detect even smaller smoke particles from smoldering flames. what is the frequency difference between the two light beams? a) 12.0 × 10^15 hzb) 3.0 × 10^15 hzc) 2.0 × 10^15 hzd) 1.0 × 10^15 hz

Frequency,

Explanation:

It is given that,

Wavelength of the light- emitting diode,

We need to find the frequency difference between the two light beams. It can be calculated using the following relation as :

So, the frequency difference between the two light beams is . Hence, this is the required solution.

positive reinforcement? ?

there is no correct list among the choices you've provided.

the list might look something like this:

-- baby human

-- piccolo

-- flute

-- soprano singer

-- trumpet

-- tenor singer

-- trombone

-- baritone singer

-- baritone horn

-- bass singer

-- tuba

since i had to make up the list myself, i made it easy on myself, and i didn't try to shuffle the string instruments and woodwinds into it too.