What magnitude charge creates a 32.08 n/c electric field at a point 2.84 m away?

Q = 29.4 x 10⁻⁹ C.

Explanation:

Electric field due to a charge Q at distance d is given by coulomb law as follows

Electric field

E = k Q /d²

where for air k which is a constant is 9 x 10⁹

Given E = 32.08 , d = 2.84 m

Putting these values in the relation above, we have

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Q = 29.4 x 10⁻⁹ C.

b.

hope this : )

it was given as a lesson and guide for prayer.