Two very small conducting spheres, each of mass 1.0x10 kg are suspended at a common point by very thin (weightless') non-conducting threads of length 0.2 m. a charge +q is placed on each sphere. suspending threads make an angle of 10. assume g-9.8 m/s2 and negligible mass for the threads. a) draw labelled force diagrams for the system b) calculate the value for q

Answer: it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.explanation:   we have equation of motion ,where s is the displacement, a is the acceleration, u is the initial velocity and t is the time taken.average velocity = displacement/ time taken.average velocity = 10.69 miles/hr = 10.69*1.6*1000/(60*60) = 4.75 m/s4.75 = s/ts = 4. 1we also have acceleration = 2.18 m/s², initial velocity = 0 m/sso it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.

Ithink it is letter b, i may be wrong but i think that is the answer

Ireally don’t know