The speed of a certain proton is 350 km/s. if the uncertainty in its momentum is 0.100%, what is the necessary uncertainty in its location?

necessary uncertainty is 0.90 nm

Explanation:

given data

speed v = 350 km/s = 350000 m/s

momentum = 0.1 %

to find out

necessary uncertainty

solution

we know here mass of proton m  is 1.6726 × g

so momentum will be  = m × v  

momentum = 1.6726 ×   × 350000

momentum = 5.85 × gm/s

momentum = 5.85 × gcm/s

and

uncertainty momentum is = 0.1 % ×  momentum

uncertainty momentum is = 0.1 % ×  5.85 ×

uncertainty momentum is = 5.85 × gcm/s

uncertainty momentum is = 5.85 × kgm/s

and we consider here dx is uncertainty position

and dp is uncertainty momentum

so dp × dx = 1/2× h     ..................1

h is plank constant that is = 1.055 × kgm²/s

so put here value in equation 1 and find dx

dx × 5.85 ×   = 1/2× 1.055 ×

dx = 9.0 ×  m

dx = 0.90 nm

so necessary uncertainty is 0.90 nm

1= 26.17

2= 1.17

3=30.86

4=5.86

just took the assigment on edge

magnified images possible images can be real = projected onto a screen