During each cycle, a heat engine ejects 75 j of thermal energy for every 115 j of input thermal energy. this engine is used to lift a 345-kg load a vertical distance of 27.0 m at a steady rate of 52.5 mm/s. part a how many cycles of the engine are needed to accomplish this task?

no of cycle required is 1885.3

Explanation:

given data

thermal energy Q1 = 75 J

thermal energy Q2 = 115 J

load = 3454 kg

distance = 27 m

steady rate = 52.5 mm/s

to find out

How many cycles of the engine are need

solution

we find here first work done that is express as

work done W = Q2 - Q1     1

put here all these value

W = 115 - 75

work done is 40 J

so energy required is

Energy required E = m×g×h     2

put here value

E = 285 × 9.8 × 27

energy required = 75411 J

so here no of cycle is

no of cycle = energy required / work done

put here value

no of cycle required = 75411 / 40

so no of cycle required is 1885.3

answer: the direction of the wind is expressed as the direction from which the wind is blowing. for example, easterly winds blow from east to west, while westerly winds blow from west to east.

explanation:

answer: at 24 february, 2014 the population gets twice of its initial population.

explanation:

since we have given that

the population for alpha city, t years after january 1, 2004 is given as

first we find out the initial population, i.e. t=0,

so, our quadratic equation becomes,

according to question, we have said that if the population has twice its initial population, then it becomes

so, time taken to reach this above mentioned population is given by

now, we know that time can't be negative so, we take t=9.149 years.

hence, at 24 february, 2014 the population gets twice of its initial population.