Ahydraulic lift has a maximum fluid pressure of 500 kpa. what should the piston/cylinder diameter be in order to lift a mass of 850 kg?

d=0.1456m =145.64mm

Explanation:

Conceptual analysis :

To solve this problem we consider the following concepts:

1)The force on a fluid is calculated as follows:

F = P*A Formula (1)

F: The force at a certain height in the fluid in (N)

P: Pressure in units of force per unit of area(N/m^2) (Pascal) (Pa)

A: cross sectional area (m2)

2) In a piston, the cross-sectional area (A) is the area of a circle and is calculated using the following formula:

Formula (2)

d: piston/cylinder diameter in (m)

3)The weight of an object (W) is calculated using the following formula:

W=m*g

Where:

W: Weight in Newtons(N)

m = mass in kg

g  = acceleration due to gravity in m/s

Known information :

We know the following data:

P = 500 kPa = 500*10^3 Pa  = 5*10^5 Pa

m =850 kg

Development of the problem :

In the formula 1:

F=P*A

d=0.1456m

d=145.64mm