Ascientist told his student assistants that he had sorted groups of mice by their intelligence and asked the assistants to assess the groups’ maze-solving abilities. the scientist had not actually sorted the mice by intelligence. the students rated the “highest intelligence” group of mice as the best maze solvers and the “lowest intelligence” group as the worst maze solvers. what was the scientist trying to demonstrate by doing this experiment?

experimental subjects should never be put into groups.
mice should not be judged by their intelligence.
higher intelligence mice are better maze solvers.
people can introduce their own biases into an experiment.

The right answer for the question that is being asked and shown above is that: "People can introduce their own biases into an experiment."  the scientist trying to demonstrate by doing this experiment is that People can introduce their own biases into an experiment.

Answer: a charge of -1.0  × 10⁻⁴ c must be placed  at x = 26 m.the sign of the charge will be the same sign as the  -4.0  µc charge.======electricstatic force between two point charges  is given by    where k is coulomb's constant,  8.99×10⁹  n·m²/c², q₁ and q₂ are the point charges, and r is the distance between the two point charges.assign positive to q₁let q₁ =  6.0 µc, q₂ = -4.0  µc, q₀ represent the charge at the origin, and q₃ represent this new charge to place.the charge at the origin q₀ would experience the following force f₀₁ from q₁, with r = 6.0 m (note that 1  µc = 10⁻⁶ c)    the force from q₂    the force from q₃    the net force on the origin charge, q₀, has to be zero for no electrostatic forcehaving an equation where k and q₀ can be divided out of the equation will allow us to solve for q₃    isolating:     a charge of -1.0  × 10⁻⁴ c must be placed  at x = 26 m.the sign of the charge will be the same as the  -4.0  µc charge