Physics, 05.09.2019 19:10 mem81

Acircular hole in an aluminum plate is 3.231 cm in diameter at 0.000°c. what is its diameter when the temperature of the plate is raised to 64.91°c? the linear expansion coefficient of aluminum is 23.00 × 10-6 /c°.

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Answer from: elizabethseoane6321

3.236 cm

Explanation:

diameter at 0°C, do = 3.231 cm

Initial temperature, To = 0° C

Final temperature, T = 64.91° C

ΔT = T - To = 64.91

Coefficient of linear expansion, α = 23 x 10^-6 / °C

Let d be the diameter when the temperature is raised.

Coefficient of areal expansion = 2 x α = 46 x 10^-6 / °C

Use the formula for the areal expansion

A = Ao(1 + βΔT)

where, ΔT be the rise in temperature.

$\frac{\pi d^{2}}{4}=\frac{\pi d_{0}^{2}}{4}\left ( 1+\beta \Delta T \right )$

$d^{2}=d_{0}^{2}\left ( 1+\beta \Delta T \right )$

$d^{2}=3.231^{2}\left ( 1+46\times10^{-6}\times 64.91\right )$

$d^{2}=10.44\left ( 1.00298\right )=10.471$

d = 3.236 cm

Thus, the diameter of the circular hole is 3.236 cm after heating at the given temperature.

Answer from: Quest

Ithink it’s cancer risk

Answer from: Quest

force is based upon mass and acceleration.the statement is not always true.

it can be explained from newton's second law of motion.

as per newton's second law of motion the rate of change of momentum is directly proportional to the applied force and takes place along the direction of force.

mathematically it can be written as -

$f\alpha \frac{dp}{dt}$

⇒ $f= k \frac{dp}{dt}$

here k is the proportionality constant whose value is 1.

$f=\frac{dp}{dt}$

$f= \frac{d[mv]}{dt}$

$f= m\frac{dv}{dt} +v\frac{dm}{dt}$

$f=ma+v\frac{dm}{dt}$ [a is the acceleration=dv/dt]

hence we see that force not only depends on mass and acceleration but also on velocity and rate of change of mass. force f will depend on mass and acceleration only when mass is constant.

hence the statement that force is based upon mass and acceleration is false.

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Acircular hole in an aluminum plate is 3.231 cm in diameter at 0.000°c. what is its diameter when th...

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