In addition to their remarkable top speeds of almost 60 mph, cheetahs have impressive cornering abilities. in one study, the maximum centripetal acceleration of a cheetah was measured to be 17 m/s2.what minimum value of the coefficient of static friction between the ground and the cheetah's feet is necessary to provide this acceleration?

coefficient of static friction is 1.7329

Explanation:

given data

velocity = 60 mph

acceleration  = 17 m/s²

to find out

coefficient of static friction

solution

we will apply here centripetal force equation

that is

m×v²/r  =  µ × m × g      1

here v²/r is centripetal acceleration and m is mass and  µ  is coefficient static friction so

µ = a / g

µ = 17 / 9.81

µ  = 1.7329

so coefficient of static friction is 1.7329

i think the answer would be reserve.

because growing process had stoped after 4-5 year