Atall tube is evacuated and its stopcock is closed. the open end of the tube is immersed in a container of water (density 10^3 kg/m^3) that is open to the atmosphere (pressure 10^5 n/m^2). when the stopcock is opened, how far up the tube will the water rise?

10.19 m

Explanation:

Water will rise to equalize the pressure inside and outside the tube.

The equation of pressure is given by

Where,

p = Pressure of air = 10⁵ N/m²

ρ = Density of water = 10³ kg/m³

g = Acceleration due to gravity = 9.81 m/s²

h = Height the water will rise

∴ The water will rise by 10.19 m.

i feel your pain too because i cant find my dad and hes been missing for 17 years of my life

explanation:

he went to the supermarket with your dad

f=ma a/f/m a= 480/60 a = 8m/s/s that is quick wow