Acar accelerated at a rate of 3ft/s^2 for 2 seconds. at the end of this time period the velocity of the car was 55ft/s what was the car's velocity before it started to accelerate?

the answer is 49ft/s

Explanation:

if you look for the equations of uniformly accelerated motion you find the following

Vo=Vf-AT

Where

Vo=initial speed

Vf=final speed

A=aceleration

T=time

you replace and it's all

Vo=55-2x3

Vo=49ft/s

0.55x745.7j and a calculator

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