Aspeeder passes a parked police car at a constant speed of 25.1 m/s. at that instant, the police car starts from rest with a uniform acceleration of 2.56 m/s 2 . how much time passes before the speeder is overtaken by the police call?

19.61 second

Explanation:

speed of speeder car, u = 25.1 m/s

initial speed of police car, u = 0

acceleration of police car, a = 2.56 m/s^2

let it take time t to overtake the speeder car.

For overtaking, the distance traveled by the speeder car in time t is same as the distance traveled by the police car.

Distance traveled by the speeder car, d = speed x time

d = 25.1 x t ..... (1)

Distance traveled by police car is given by second equation of motion

d = 1.28t^2     .... (2)

From equation (1) and (2) we get

25.1 t = 1.28 t^2

25.1 = 1.28 t

t = 19.61 second

the small 0.38-kg slider is known to move from position a to position b along the vertical-plane slot. determine (a) the work done on the body by its weight and (b) the work done on the body by the spring. the distance r = 0.70 m, the spring modulus k = 154 n/m, and the unstretched length of the spring is 0.53 m

explanation:

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