You attach a 2.90 kg mass to a horizontal spring that is fixed at one end. you pull the mass until the spring is stretched by 0.500 m and release it from rest. assume the mass slides on a horizontal surface with negligible friction. the mass reaches a speed of zero again 0.300 s after release (for the first time after release). what is the maximum speed of the mass (in m/s)?

Explanation:

The spring is stretched by .5 m and then released that means its amplitude of oscillation A is 0.5 m .

A = 0.5 m

After the release at one extreme point , the mass comes to rest again at another extreme point after half the time period ie

T / 2 = .3 s

T = 0.6 s

Angular velocity

ω =

ω =

ω = 10.45

Maximum velocity  = ω A

ω and  A are angular velocity and amplitude of oscillation.

Maximum velocity  = 10.45 x .5

= 5.23 m /s

part 1: which substance has a higher solubility?

a

smallest amount left undissolved atall temps in table shown most has dissolved high sol'by

the right answer is 0.3 meters per second