If the passenger is 3.2m above her friend when the camera is tossed, what is the minimum initial speed of the camera, if it is to just reach the passenger? (hint: when the camera is thrown with its minimum speed, its speed on reaching the passenger is the same as the speed of the passenger.)

The minimum velocity required is 7.923 m/s

Explanation:

The minimum speed required shall be equal to the speed that allows the camera to just reach a height of 3.2 meters

This can be solved using the third equation of kinematics as

where

v = final speed of object

u = initial speed of object

s = is the height attained

Since finally velocity becomes zero thus the above equation reduces to

e

explanation:

there is no change in the electric potential energy as it is in rest on both conditions.