Aphoton of wavelength 2.78 pm scatters at an angle of 147° from an initially stationary, unbound electron. what is the de broglie wavelength of the electron after the photon has been scattered?

2.07 pm

Explanation:

The problem given here is the very well known Compton effect which is expressed as

here, is the initial photon wavelength, is the scattered photon wavelength, h is he Planck's constant, is the free electron mass, c is the velocity of light, is the angle of scattering.

Given that, the scattering angle is,

Putting the respective values, we get

Here, the photon's incident wavelength is

Therefore,

From the conservation of momentum,

where, is the initial photon momentum, is the final photon momentum and is the scattered electron momentum.

Expanding the vector sum, we get

Now expressing the momentum in terms of De-Broglie wavelength

and putting it in the above equation we get,

Therefore,

This is the de Broglie wavelength of the electron after scattering.

from

explanation:

wind is defined by the direction it blows from.   for example, a wind blowing from north to south is called a northerly wind.

they are non-matter

explanation:

they are non-matter. basically, any type of energy or any abstract concept is an example of something that does not matter. other examples include dreams, magnetism, radio, and hate