Atank whose bottom is a mirror is filled with water to a depth of 20.6 cm . a small fish floats motionless 7.80 cm under the surface of the water. part a
what is the apparent depth of the fish when viewed at normal incidence to the water?
express your answer in centimeters. use 1.33 for the index of refraction of water.
part b
what is the apparent depth of the reflection of the fish in the bottom of the tank when viewed at normal incidence?
express your answer in centimeters. use 1.33 for the index of refraction of water.

Explanation:

A )  Index of refraction = real depth / apparent depth

real depth = 7.8 cm  ; Index of refraction = 1.33

1.33 = 7.8 /apparent depth

apparent depth = 7.8 / 1.33

= 5.86 cm

B )  

Distance of fish fro mirror = 20.6 - 7.8 = 12.8 cm

Image will be formed 12.8 cm behind the mirror.

Distance of image from the water surface = 20.6 +12.8

= 33.4 cm

Real depth of image = 33.4

Apparent depth of image  = 33.4 / 1.33

= 25.11 cm

we have been given a quadratic function and we need to restrict the domain such that it becomes a one to one function.

we know that vertex of this quadratic function occurs at (5,2).

further, we know that range of this function is .

if we restrict the domain of this function to either or , it will become one to one function.

let us know find its inverse.

upon interchanging x and y, we get:

let us now solve this function for y.

hence, the inverse function would be if we restrict the domain of original function to and the inverse function would be if we restrict the domain to .

a sonic boom is a loud boom that breaks the sound barrier

explanation: