The resistanceless inductor is connected across the ac source whose voltage amplitude is 24.5 v and angular frequency is 850 rad/s . find the current amplitude if the self-inductance of the inductor is: part a: 1.00×10−2 h . answer in a.
part b: 1.00 h . answer in ma.
part c: 100 h . answer in ma.

Part A 2.88 A, PART B 28.82 mA PART C  0.288 mA

Explanation:

We have given angular frequency

Voltage source has an amplitude of 24.5 V, So V= 24.5 volt

Part A

We have given inductance

So inductive reactance

So current

Part B

We have given inductance

So inductive reactance

So current

Part C

We have given inductance

So inductive reactance

So current

the answer for apex is the lowest