You and a friend each drive 49 km to the same destination. you travel at 89.3 km/h and your friend at 98.2 km/h. how long will your friend wait for you at the end of the trip? answer in units of min.

time, t = 3.6 min

Given:

Distance covered, d = 49 Km

My travel speed, v = 89.3 km/h

Friend's travel speed, v' = 98.2 km/h

Solution:

From the formula of speed, distance and time:

Time taken by me, T;

Now,

Time taken by friend:

Friend's wait time, t = T - T' = 0.55 - 0.49 = 0.06 h

In minutes;

t =

  1.the balanced   chemical equation is as below

cu +   2 ag(no)₃ → cu(no₃)₂   +2 ag

2.the   much silver   produced   is   50.9 g

step 1: find the   moles of cu

moles =   mass÷   molar mass

  from periodic table the molar mass of cu = 63.5 g/mol

moles is therefore = 15.00 g÷ 63.5 g/mol = 0.236   moles

step 2: use the mole ratio to determine the   moles of ag

from equation above   cu: ag   is 1: 2

therefore the moles of ag   =0.236   moles   x 2/1 =0.472   moles

step 3: find the mass   of ag

mass = moles x molar mass

from periodic table   the molar mass of ag =107.87 g/mol

mass   = 0.472   moles x 107.87 g/mol = 50.9 g

3.   the   much   silver   collected worth is   1.797 oz

  convert   50.9 g   to oz

that is   1 gram = 0.0353 oz

          50.9 grams =?   oz

by cross multiplication

={(50.9 grams x 0.0353 oz) / 1   gram}   =1.797 oz

where’s the list ? the question is incomplete