Aboat radioed a distress call to a coast guard station. at the time of the call, a vector a from the station to the boat had a magnitude of 45.0 km and was directed 15.0° east of north. a vector from the station to the point where the boat was later found is b = 30.0 km, 15.0° north of east.
how far did the boat travel from the point where the distress call was made to the point where the boat was found? in other words, what is the magnitude of vector c?
a)65.3 km
b)39.7 km
c)26.5 km
d)54.0 km
e)42.5 km

d = 39.7 km

Explanation:

initial position of the boat is 45 km away at an angle of 15 degree East of North

so we will have

after some time the final position of the boat is found at 30 km at 15 Degree North of East

so we have

now the displacement of the boat is given as

so the magnitude is given as

as we know our atmosphere or air have different levels. every level has other gasses, and every gas has another permeability. when the light comes from lower permeability to higher permeability, it changes its direction. so that means that when the light comes from the moon to the earth, it changes it's direction many more times. it basically means that the shape of the light part of the moon is changed on the earth.

hope this ! this is not copied! search it up, it's free of plagiarism!

you get 2.3=1.21*\frac{a}2 or 4.6=1.21a or a=3.802 (b)

explanation: