Acar traveling at a speed of v can brake to an emergency stop in a distance x , assuming all other driving conditions are all similar , if the traveling speed of the car double, the stopping distance will be (1) √2x,(2)2x, or(3) 4x: (b) a driver traveling at 40.0km/h in school zone can brake to an emergency stop in 3.00m. what would be braking distance if the car were traveling at 60.0 km/h?

D = 6.74 m

Explanation:

Let the f newtons  be the braking force

distance to stop =  x meters

speed =  v m/s

we know that work done is given as

work done W = fx joules

If the speed is doubled ,

stooping distance is D = 4x

60 km/hr = 16.66 m/s  

braking force = f

D = 6.74 m

gpe = mass x gravity constant x height or… gpe = mgh

where… mass: measured in kilograms (kg)

gravity: gravity constant on earth = 10.00 m/s2

height: measured in meters (m)

gpe: measured in joules (j) or kilojoules (kj)

how do you solve gpe?

gravitational potential energy (gpe) is the energy an object has because of its position above the. ground.

gpe = mass x gravity constant x height or… gpe = mgh.

mass:

note: to earn full marks when solving science word problems, you must show your work:

formula.

example:

given values:

mass = 0.3 kg.