Use this simulation of a lunar lander to understand the motion of an object under various force conditions. you can change the direction and the thrust applied to the lunar lander in this activity. observe how the position, velocity, and altitude of the lunar lander change with a change in thrust. answer the following questions based on these observations and the instructions given with each of them. part a observe the vertical and horizontal motion of the lunar lander in the absence of thrust. explain the reason for this motion.

Distance covered, s = 8ft - 4ft = 4 ftinitial velocity, u = 34 ft/sthe acrobat is moving upwards and therefore, a = -g = -9.81 m/s^2 = 32.19 ft/s^2applying equation of motion; s = ut -1/2gt^2then,4 = 34t -1/2*32.19t^24 = 34t - 16.095t^2rearranging; -16.095t^2 + 34t - 4 = 0solving the quadratic equation; t = {-34 +/- sqrt [34^2 - 4(-16.)]}/2(-16.095) = 1.06 +/- 0.93 = 0.13 or 1.99the acrobat will take 0.13 seconds to be at 8 ft above the ground. additionally, once at the maximum height, the acrobat will move down and be at the same spot (that is height) after 1.99 seconds moving down.

The statement that best describes the object on the right is a bar magnet with its north pole on the left.