Asquare coil with 100 turns of wire has sides of length 5 cm. the resistance of the coil is 12.0 ω. the coil is placed in a uniform magnetic field that is perpendicular to the face of the coil and whose magnitude is decreasing at a rate of 0.081 t/s. what is the magnitude of the current circulating through the coil?

The magnitude of the current circulating through the coil is 1.68 mA.

Explanation:

Given that,

Number of turns = 100

Length = 5 cm

Resistance = 12.0 Ω

Rate of magnetic field = 0.081 T/s

We need to calculate the magnitude of the current circulating through the coil

Using formula of current

Where, A = area

N = number of turns

R = resistance

Put the value into the formula

Hence, The magnitude of the current circulating through the coil is 1.68 mA.

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explanation:

what is the speed of a softball that travels 20m in 2secs

speed = 20/2 = 10 m/s