The total length of the cord is l = 7.00 m, the mass of the cord is m = 7.00 g, the mass of the hanging object is m = 2.50 kg, and the pulley is a fixed a distance d = 4.00 m from the wall. you pluck the cord between the wall and the pulley and it starts to vibrate. what is the fundamental frequency (in hz) of its vibration?

frequency = 19.56 Hz

Explanation:

given data

length L = 7 m

mass m = 7 g

mass M = 2.50 kg

distance d = 4 m

to find out

fundamental frequency

solution

we know here frequency formula is

frequency =   ...........1

so here d is given = 4

and v =  ..........2

tension T = Mg = 2.50 × 9.8 = 24.5 N

and μ = =   = kg/m

so from equation 2

v =

v = 156.52

and from equation 1

frequency =

frequency =

frequency = 19.56 Hz

the higher the current the higher the mag field around it the higher the influence on the compass

force is based upon mass and acceleration.the statement is not always true.

it can be explained from newton's second law of motion.

as per newton's second law of motion the rate of change of momentum is directly proportional to the applied force and takes place along the direction of force.

mathematically it can be written as -

                                              ⇒      

here   k is the proportionality constant whose value is 1.

                                                            [a is the acceleration=dv/dt]

hence we see that force not only depends on mass and acceleration but also on velocity and rate of change of mass. force f will depend on mass and acceleration only when mass is constant.

hence the statement that force is based upon mass and acceleration is false.