Two of the types of infrared light, ir-c and ir-a, are both components of sunlight. their wavelengths range from 3000 to 1,000,000 nm for ir-c and from 700 to 1400 nm for ir-a. compare the energy of microwaves, ir-c, and ir-a.

Explanation:

3000 to 1,000,000 nm for IR-C

700 to 1400 nm for IR-A

Now, we are working with light, so we can use that the energy of a photon with frequency f is : E(f) = h*f

where h is the plank constant h = 6.62607015×10−34 j*s

and f is the frequency that f= c/λ, where λ is the wavelenght.

so, for IR-C the energy lies between h*c/3000 and h*c/1000000

where c is the light speed.

For IR-A the energy lies between h*c/700 and h*c/1400.

so here you can se that IR-A has a lot more energy than IR-C, you can se that the minimal energy of IR-A is h*c/1400 and the maximal of IR-C is h*c/3000 so the minimal energy of IR-A is almost twice times the maximum energy of IR-C

the answer is 3.1 his answer is wrong mines is right

a is the best answer your welcome