A0.650 kg block is attached to a spring with spring constant 18.0 n/m . while the block is sitting at rest, a student hits it with a hammer and almost instantaneously gives it a speed of 47.0 cm/s . what are
the amplitude of the subsequent oscillations? answer is in cm
the block's speed at the point where x= 0.350 a? answer is in cm/s

amplitude is 8.92 cm

speed of block is 44.11 cm/s

Explanation:

given data

mass = 0.650 kg

spring constant = 18 N/m

speed = 47 cm/s = 0.44 m/s

speed at x point = 0.350 A

to find out

amplitude of subsequent oscillation

solution

we know here conservation of energy

maximum kinetic energy = maximum potential energy

here we know k is spring constant and m is mass and A is amplitude and v is velocity

so solve it we get

A =

put here all these value

A =  

A = 0.08931 m

so amplitude is 8.92 cm

and

by conservation of energy

initial energy = final energy

=

solve we gey V

V =    

put here value Vm = 0.47 , and x = 0.350

V =

V = 0.4411 m/s

so speed of block is 44.11 cm/s

i think the answer is a, hope this : )

i had this question and the answer was 3.15 miles.

martina travels from school to her mom's office. from there, she walks to school. after school, she walks to the library and then to a friends house before finally ending back at home. find martina's total distance traveled.

a) 0 miles  

b) 0.4 miles  

c) 1 mile  

d) 3.15 miles