Calculate the electric field at the center of a square 42.5cm on a side if one corner is occupied by a -38.6 microcoulomb charge and the other three are occupied by -27.0 microcoulomb charges?

The answer is .

Explanation:

Using the Pythagorean theorem, the distance between the center of the square and each corner is

being d the length of one side of the square (42.5 cm = 0.425 m).

The electric field due to a point charge at a distance r from it is

( is the vacuum permittivity).

The electric field due to the two charges of located at opposite corners of the square is zero, because both charges are equal and are at the same distance from the center but in opposite directions. So the problem is reduced to the electric field at the center of a line between two charges of and at a distance r from the center.

Applying the last equation,

.

Considering and and

(opposite directions), the electric field is

.

The negative sign and indicate that the direction of the field is towards the charge .

  distance on the y-axis and time on the x-axis.

explanation:

the instantaneous velocity = change in position/time taken

the slope of the graph should give instantaneous velocity.

  slope of a graph = change in value of y -axis / change in values of x -axis

  comparing both the equations

    change in value of y -axis = change in position

  change in values of x -axis = time taken

so position values should be on the y axis and time values should be on the x axis.

distance on the y-axis and time on the x-axis.

there are no components of a physical goal mentioned on the list of choices that you've provided.