Two tiny conducting sphere are identical and carry charges of -20 μc and +50 μc. they are separated by a distance of 2.50 cm. what is the magnitude of the force that each sphere experiences, and is the force attractive or repulsive?

Force between two spheres will be 14400 N

And as the both charges of opposite nature so force will be attractive

Explanation:

We have given two conducting spheres of charges

Distance between the spheres = 2.5 cm =0.025 m

According to coulombs law we know that force between two charges is given by  

As the both charges of opposite nature so force will be attractive

found in the nucleus

has mass of one amu

we're given that v₀ = 0 and a = 5.4 m/s². therefore, since v = at + v₀ for constant acceleration the equation for velocity is

after 28s,

m/s

which i would round to 150 m/s as my final answer