38.4 mol of krypton is in a rigid box of volume 64 cm^3 and is initially at temperature 512.88°c. the gas then undergoes isobaric heating to a temperature of 935.9°c. (a) what is the final volume of the gas? (in cm^3 ) (b) it is then isothermally compressed to a volume 29.3cm^3; what is its final pressure? (in pa )

Final volumen first process

Final Pressure second process

Explanation:

Using the Ideal Gases Law yoy have for pressure:

where:

P is the pressure, in Pa

n is the nuber of moles of gas

R is the universal gas constant: 8,314 J/mol K

T is the temperature in Kelvin

V is the volumen in cubic meters

Given that the amount of material is constant in the process:

In an isobaric process the pressure is constant so:

Replacing :

Replacing on the ideal gases formula the pressure at this piont is:

For Temperature the ideal gases formula is:

For the second process you have that  So:

the answer is a 3.8cm

explanation: