Astone is thrown directly upward with an initial speed of 9.6 m/s from a height of 12.8 m. after what time interval (in s) does the stone strike the ground? use g 9.8 m/s^2 enter a number with 2 digits behind the decimal point.

1.89 seconds

Explanation:

t = Time taken

u = Initial velocity = 9.6 m/s

v = Final velocity

s = Displacement

a = Acceleration due to gravity = 9.81 m/s²

Time taken to reach maximum height is 0.97 seconds

So, the stone would travel 4.7 m up

So, total height ball would fall is 4.7+12.8 = 17.5 m

Time taken by the stone to travel 17.5 m is 1.89 seconds

can u provide the graph and if its not possible

then i can tell u the segment where the

average time interval starts degrading is the segment where the car is slowing down