At the instant the traffic light turns green, a car starts with a constant acceleration of 8.00 ft/s^2. at the same instant a truck, traveling with a constant speed of 10.0 ft/s, overtakes and passes the car. how far from the starting point (in feet) will the car overtake the truck?

they meet at distance 25 feet

Explanation:

given data

acceleration of car  = 8 ft/s²

truck speed = 10 ft/s

car initial speed u = 0

truck acceleration = 0

to find out

How far from the starting point will car overtake the truck

solution

we apply here equation of motion

s = ut + 0.5 ×a×t²   1

here s is distance and a is acceleration and t is time u is initial speed

so truck distance

s = 10t + 0.5 ×0×t²

s = 10 t   2

and car distance

s = 0+ 0.5 ×8×t²  

s = 4×t²     3

so from equation 2 and 3

10 t = 4×t²

t = 2.5 s

so both meet at distance

s = 10 (t)

s = 10 ( 2.5 ) = 25 ft

so they meet at distance 25 feet

the answer is 100. i just did this lesson and got a 100% on it. : )

-fishtank