Askateboarder starts up a 1.0-m-high, 30° ramp at a speed of 7.6 m/s . the skateboard wheels roll without friction. at the top, she leaves the ramp and sails through the air. how far from the end of the ramp does the skateboarder touch down?

t = 1.084 s

s = 8.25 m

Explanation:

given,

height from where skate board start (h) = 1 m

speed = 7.6 m/s

we know

v² = u² + 2 g h                      

v² =7.6² + 2×9.81× 1

v = 8.79 m/s                        

t = 1.084 s

then horizontal distance

s = 8.25 m

i believe the answer is a

acceleration = (change in speed) / (time for the change)

change in speed = (20-120)= -100 m/s.

1.5 min = 90 sec

acceleration = -100/90 = -1.11 m/s^2.

we don't care about the 150kg or the 2,500 meters. they don't make any difference.

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