Acar and a motorcycle start from rest at the same time on a straight track, but the motorcycle is 25.0 m behind the car. the car accelerates at a uniform rate of 3.70 m/s^2 and the motorcycle at a uniform rate of 4.40 m/s^2. how much time elapses before the mc overtakes the car? how far will each have traveled during that time?

t = 8.45 sec

car distance d = 132.09  m

bike distance d = 157.08 m

Explanation:

GIVEN :

motorcycle is 25 m behind the car , therefore distance need to covered by bike to overtake car is 25+ d, when car reache distance d at time t

for car

by equation of motion

u = 0 starting from rest

for bike

equating time of both

solving for d we get

d = 132 m

therefore t is

t = 8.45 sec

each travelled in time 8.45 sec as

for car

d = 132.09  m

fro bike

d = 157.08 m

not too sure thinking all accelerations are pointed down