If a body travels half it’s total path in the last 1.10s if it’s fall from rest, find the total time of its fall (in seconds)

3.75s

Explanation:

We can use the equations for constant acceleration motion. Let's call x, the total length of the path, then x/2 will be half of path. After falling from rest and reaching the half of its total path, the velocity of the body will be:

vf is the final velocity, v0 is the initial velocity, 0m/s because the body starts from rest. a is the acceleration, gravity = 9.81m/s^2 in this case. Now, clearing vf we get:

Solving for x, you get that x is equal to 69.2 m or 2.03m. The total time of the fall would be:

Trying both possible values of x:

t2  is lower than 1.1s, therefore is not a real solution.

Therefore, the path traveled will be 69.2m and the total time 3.75s

where is the circuit diagram ?